- Approximately what time of day the photo was taken at, or if it's computer-generated
- Which parts of the photo were computer-generated, if any
- The season (for outdoor photos)

House |

Crayons |

Calendar Blue Moon |

Weeds and Grass |

Here are some pictures I took. See if you can guess some things about the photos:

- Approximately what time of day the photo was taken at, or if it's computer-generated
- Which parts of the photo were computer-generated, if any
- The season (for outdoor photos)

House |

Crayons |

Calendar Blue Moon |

Weeds and Grass |

Diving can be done well or poorly, depending on how good the diver is. Sometimes, beginning divers will do "belly flops", smacking the water horizontally instead of cutting into it like a needle. Whether a dive is a good one usually depends on whether the diver went straight into the water or not. Experienced divers can do this without thinking much about it, as if it were like walking; beginners, however, have a lot more trouble.

In time, people get used to diving; machines, however, can't learn, and are always just as clumsy. If the machine contained a computer, it would need a computer program to help it dive. The program would need to use a math formula. Here's what we'll start out with:* v*_{1}=* v*_{2}* *tan *θ*, where *v*_{1} and *v*_{2} represent forward and downward velocities, and *θ* is the vertical angle in degrees.

Here's how it works: the forward and downward velocities of a good dive have the same ratio as the sine and cosine of the vertical angle of the diver (represented by *θ*. See picture), so the formula is *v*_{1}* */* **v*_{2} = sin *θ** */ cos *θ*. Since sin/cos = tan, the formula becomes *v*_{1} / *v*_{2} = tan *θ*; multiply both sides by *v*_{2}, and you get *v*_{1}* *= *v*_{2} tan *θ*.

To use the formula, you figure out what angle you'll be diving at and how fast you'll be falling when you hit the water (the downward velocity, *v*_{2}). When you put those numbers into the equation, you can do the math and get your forward velocity (*v*_{1}), so you know how fast you have to run off the diving board.

However, you might not know how fast you'll be falling (*v*_{2}) when you hit the water, so let's calculate it now. If you fell *h* feet in *s* seconds, your average speed in the time you fell was *h* ft per *s* sec, which is the same speed as *h*/*s* ft per sec. Since acceleration while falling is as good as a constant (ignoring air resistance), and you start at zero, your final speed is twice your average speed: 2*h*/*s* ft per sec. Insert that into the equation and you get:

Now we have another problem: *s*, the amount of time before you hit the water. To get rid of *s*, we just need to state it in terms of another variable. After falling for 1 second, your speed will be 32 ft per sec. After *s* seconds, your speed will be 32*s* ft per sec. We also know that your speed will be 2*h*/*s* ft per sec. Therefore, 2*h*/*s* = 32*s*. Work it out and you get *s* = √*h* / 4. The very complicated equation you see to the right is what we have now. And if we simplify it, we get the final equation you see below.

Subscribe to:
Posts (Atom)